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Description: C++语言实现的rsa加密算法，共同学习-C language of rsa encryption algorithm, learning together
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Size: 2620 |
Author: ly |
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Description: RSA算法C++实现，在VC6.0下编译通过
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Size: 134508 |
Author: 458686683@qq.com |
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Description: RSA加密/解密算法源码 -RSA encryption and decryption algorithm source code
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Size: 3072 |
Author: 站长 |
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Description: rsa加解密程序-rsa encryption and decryption process
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Size: 53248 |
Author: chenzhilun |
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Description: 一个关于密码算法RSA的实现程序- About crypto-algorithm RSA realization procedure
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Size: 1975296 |
Author: 李素芝 |
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Description: RSA算法的源码，出自高手 VC。-RSA algorithm source code, stems from master VC.
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Size: 10240 |
Author: 张灵飞 |
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Description: RSA加密解密源码-RSA encryption decipher source code
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Size: 350208 |
Author: 刘高 |
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Description: rsa加密算法源程序-rsa encryption algorithm source code
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Size: 21504 |
Author: 王珺 |
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Description: RSA加密解密及RSA签名和验证算法，c/s界面，-RSA encryption and decryption and validation of signatures RSA algorithm, c/s interface,
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Size: 3072 |
Author: 方良 |
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Description: RSA C++代码-RSA C code
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Size: 134144 |
Author: 施向东 |
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Description: rsa加密算法实例-rsa encryption algorithm examples
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Size: 16384 |
Author: 张飞 |
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Description: 这里有大量的加密程序有RSA,MD5等都可以运行且没有错快快用吧-here a large number of RSA encryption procedure, MD5 can all be run with no mistakes quickly and use it
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Size: 2022400 |
Author: 闾凡兵 |
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Description: RSA DES 等几个算法的C程序,不要错过-several RSA DES algorithm C program should not miss
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Size: 56320 |
Author: 李鹏 |
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Description: RSA算法 :首先, 找出三个数, p, q, r, 其中 p, q 是两个相异的质数, r 是与 (p-1)(q-1) 互质的数...... p, q, r 这三个数便是 person_key，接著, 找出 m, 使得 r^m == 1 mod (p-1)(q-1)..... 这个 m 一定存在, 因为 r 与 (p-1)(q-1) 互质, 用辗转相除法就可以得到了..... 再来, 计算 n = pq....... m, n 这两个数便是 public_key ，编码过程是, 若资料为 a, 将其看成是一个大整数, 假设 a < n.... 如果 a >= n 的话, 就将 a 表成 s 进位 (s <= n, 通常取 s = 2^t), 则每一位数均小于 n, 然後分段编码...... 接下来, 计算 b == a^m mod n, (0 <= b < n), b 就是编码后的资料。解码的过程是, 计算 c == b^r mod pq (0 <= c < pq), 于是, 解码完毕-RSA algorithm : First, find a few 3, p, q, r, p, q is the two different prime number, with the r (p-1) (q-1) coprime several ... p, q, r it person_key number is three, and then find m, making r ^ m == a mod (p-1) (q-1 m ...................................... this must exist, because r (p-1) (q- 1) coprime, with the division algorithm can be a ..... Next, calculate n = pq ....... m, n is the number two public_key, coding process is that if a data and to treat it as a big Integer assuming a <n. ... If a> = n, a table will be rounding into s (s <= n, usually from 2 ^ s = t), each n is less than the median, and then sub-coding ..... . Next, calculate a == b ^ m mod n, (0 <= b <n), b is encoded information. Decoding is the process of calculating c == b ^ r mod pq (0 <= c &
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Size: 1024 |
Author: 胡康康 |
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Description: RSA加密处理C#代码研究 1、生成public key和private key并可保存生成XML文件。 2、演示了RSA数字签名的处理过程。 3、演示了加密解密的过程。 -RSA encryption code research C# 1, and generated public key can be kept private key to generate XML documents. 2, demonstrated a RSA digital signature of the process. 3, demonstrated the encryption and decryption process.
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Size: 2048 |
Author: LJ |
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Description: 实现RSA加密算法的c++源代码-achieve RSA encryption algorithm source code c
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Size: 81920 |
Author: 张兵 |
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Description: RSA算法的VC实现，其中包括超长整数类，素数检验算法，大素数生成器和一般的数论算法，例如中国剩余定理解密RSA密文-RSA algorithm VC, including long integer type, in a few test algorithm, large prime number generator and the general theory of numbers algorithm, for example, Chinese Remainder Theorem RSA decryption ciphertext
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Size: 258048 |
Author: 陈建湘 |
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Description: OpenSSL的RSA算法应用举例。是用VC写的，有实用价值。-RSA algorithm of OpenSSL is used and given an example. Written with VC, there is practical value.
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Size: 18432 |
Author: 王尔德 |
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Description: rsa加密算法的vc实现，可以实现1024位的加密-the source code of rsa algorithm in vc,which can do 1024bits encryption.
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Size: 148480 |
Author: 李 |
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Description: RSA加密解密算法，实现RSA的基本功能，一般的算法RSA.C-RSA encryption and decryption algorithms, to achieve the basic functions of RSA, the general algorithm RSA.CPP
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Size: 4096 |
Author: sdtcool |
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